13194139533349 has 2 divisors, whose sum is σ = 13194139533350. Its totient is φ = 13194139533348.

The previous prime is 13194139533299. The next prime is 13194139533371. The reversal of 13194139533349 is 94333593149131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12732443745025 + 461695788324 = 3568255^2 + 679482^2 .

It is a cyclic number.

It is not a de Polignac number, because 13194139533349 - 2¹¹ = 13194139531301 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13194139533293 and 13194139533302.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13194139533389) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (5) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6597069766674 + 6597069766675.

It is an arithmetic number, because the mean of its divisors is an integer number (6597069766675).

Almost surely, 2^{13194139533349} is an apocalyptic number.

It is an amenable number.

13194139533349 is a deficient number, since it is larger than the sum of its proper divisors (1).

13194139533349 is an equidigital number, since it uses as much as digits as its factorization.

13194139533349 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 14171760, while the sum is 58.

The spelling of 13194139533349 in words is "thirteen trillion, one hundred ninety-four billion, one hundred thirty-nine million, five hundred thirty-three thousand, three hundred forty-nine".