Base | Representation |
---|---|
bin | 11000100101000001… |
… | …01111011100001111 |
3 | 1021001121121120100022 |
4 | 30102200233130033 |
5 | 204011020142303 |
6 | 10021212452355 |
7 | 644665453505 |
oct | 142240573417 |
9 | 37047546308 |
10 | 13195474703 |
11 | 56615574a4 |
12 | 268317a0bb |
13 | 1323a332c8 |
14 | 8d26d0675 |
15 | 5236b5438 |
hex | 31282f70f |
13195474703 has 2 divisors, whose sum is σ = 13195474704. Its totient is φ = 13195474702.
The previous prime is 13195474697. The next prime is 13195474741. The reversal of 13195474703 is 30747459131.
13195474703 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (30747459131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13195474703 - 220 = 13194426127 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13195474763) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6597737351 + 6597737352.
It is an arithmetic number, because the mean of its divisors is an integer number (6597737352).
Almost surely, 213195474703 is an apocalyptic number.
13195474703 is a deficient number, since it is larger than the sum of its proper divisors (1).
13195474703 is an equidigital number, since it uses as much as digits as its factorization.
13195474703 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 317520, while the sum is 44.
The spelling of 13195474703 in words is "thirteen billion, one hundred ninety-five million, four hundred seventy-four thousand, seven hundred three".
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