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13199304749 is a prime number
BaseRepresentation
bin11000100101011110…
…10110100000101101
31021001212211011011212
430102233112200231
5204013010222444
610021430524205
7645043145021
oct142257264055
937055734155
1013199304749
115663733024
122684506665
1313247746c7
148d300a381
15523bc019e
hex312bd682d

13199304749 has 2 divisors, whose sum is σ = 13199304750. Its totient is φ = 13199304748.

The previous prime is 13199304647. The next prime is 13199304761. The reversal of 13199304749 is 94740399131.

13199304749 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13097658025 + 101646724 = 114445^2 + 10082^2 .

It is a cyclic number.

It is not a de Polignac number, because 13199304749 - 228 = 12930869293 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13199304697 and 13199304706.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13199307749) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6599652374 + 6599652375.

It is an arithmetic number, because the mean of its divisors is an integer number (6599652375).

Almost surely, 213199304749 is an apocalyptic number.

It is an amenable number.

13199304749 is a deficient number, since it is larger than the sum of its proper divisors (1).

13199304749 is an equidigital number, since it uses as much as digits as its factorization.

13199304749 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 734832, while the sum is 50.

The spelling of 13199304749 in words is "thirteen billion, one hundred ninety-nine million, three hundred four thousand, seven hundred forty-nine".