13200003111133 has 4 divisors (see below), whose sum is σ = 13328158481248. Its totient is φ = 13071847741020.

The previous prime is 13200003111121. The next prime is 13200003111151. The reversal of 13200003111133 is 33111130000231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13200003111133 - 2¹³ = 13200003102941 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13200003111133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13200003111193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64077684903 + ... + 64077685108.

It is an arithmetic number, because the mean of its divisors is an integer number (3332039620312).

Almost surely, 2^{13200003111133} is an apocalyptic number.

It is an amenable number.

13200003111133 is a deficient number, since it is larger than the sum of its proper divisors (128155370115).

13200003111133 is a wasteful number, since it uses less digits than its factorization.

13200003111133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 128155370114.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 13200003111133 its reverse (33111130000231), we get a palindrome (46311133111364).

The spelling of 13200003111133 in words is "thirteen trillion, two hundred billion, three million, one hundred eleven thousand, one hundred thirty-three".