1320002011020 has 384 divisors, whose sum is σ = 4684809830400. Its totient is φ = 269734348800.

The previous prime is 1320002011001. The next prime is 1320002011039. The reversal of 1320002011020 is 201102000231.

It is an interprime number because it is at equal distance from previous prime (1320002011001) and next prime (1320002011039).

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a junction number, because it is equal to n+sod(n) for n = 1320002010987 and 1320002011005.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 134155261 + ... + 134165099.

It is an arithmetic number, because the mean of its divisors is an integer number (12200025600).

Almost surely, 2^{1320002011020} is an apocalyptic number.

1320002011020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1320002011020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2342404915200).

1320002011020 is an abundant number, since it is smaller than the sum of its proper divisors (3364807819380).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1320002011020 is a wasteful number, since it uses less digits than its factorization.

1320002011020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10349 (or 10347 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 12.

Adding to 1320002011020 its reverse (201102000231), we get a palindrome (1521104011251).

The spelling of 1320002011020 in words is "one trillion, three hundred twenty billion, two million, eleven thousand, twenty".