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13200043540 = 2251793687163
BaseRepresentation
bin11000100101100100…
…01010111000010100
31021001221012200121111
430102302022320110
5204013202343130
610021454424404
7645052342645
oct142262127024
937057180544
1013200043540
1156640980a2
122684802104
131324972a68
148d315d6cc
15523cb902a
hex312c8ae14

13200043540 has 24 divisors (see below), whose sum is σ = 27874959840. Its totient is φ = 5250518688.

The previous prime is 13200043529. The next prime is 13200043543. The reversal of 13200043540 is 4534000231.

It is a super-2 number, since 2×132000435402 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13200043543) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1840002 + ... + 1847161.

It is an arithmetic number, because the mean of its divisors is an integer number (1161456660).

Almost surely, 213200043540 is an apocalyptic number.

13200043540 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13200043540 is an abundant number, since it is smaller than the sum of its proper divisors (14674916300).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13200043540 is a wasteful number, since it uses less digits than its factorization.

13200043540 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3687351 (or 3687349 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 22.

Adding to 13200043540 its reverse (4534000231), we get a palindrome (17734043771).

The spelling of 13200043540 in words is "thirteen billion, two hundred million, forty-three thousand, five hundred forty".

Divisors: 1 2 4 5 10 20 179 358 716 895 1790 3580 3687163 7374326 14748652 18435815 36871630 73743260 660002177 1320004354 2640008708 3300010885 6600021770 13200043540