132001113100221 has 8 divisors (see below), whose sum is σ = 195557204592960. Its totient is φ = 88000742066796.

The previous prime is 132001113100177. The next prime is 132001113100253. The reversal of 132001113100221 is 122001311100231.

132001113100221 is a `hidden beast` number, since 1 + 3 + 20 + 0 + 111 + 310 + 0 + 221 = 666.

It is not a de Polignac number, because 132001113100221 - 2⁴⁶ = 61632368922557 is a prime.

It is a super-2 number, since 2×132001113100221² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132001113100194 and 132001113100203.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132001113100121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2444465057385 + ... + 2444465057438.

It is an arithmetic number, because the mean of its divisors is an integer number (24444650574120).

Almost surely, 2^{132001113100221} is an apocalyptic number.

It is an amenable number.

132001113100221 is a deficient number, since it is larger than the sum of its proper divisors (63556091492739).

132001113100221 is an equidigital number, since it uses as much as digits as its factorization.

132001113100221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4888930114832 (or 4888930114826 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 132001113100221 its reverse (122001311100231), we get a palindrome (254002424200452).

The spelling of 132001113100221 in words is "one hundred thirty-two trillion, one billion, one hundred thirteen million, one hundred thousand, two hundred twenty-one".