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132001120113300 = 2232523773101537637
BaseRepresentation
bin11110000000110111100111…
…110111111101001010010100
3122022101011222000112210022200
4132000313213313331022110
5114300201243222111200
61144424251042524500
736542523545053134
oct3600674767751224
9568334860483280
10132001120113300
11390723a7050789
121297a850066730
135886862bc0099
142484c61704ac4
15103d9baa81800
hex780de7dfd294

132001120113300 has 432 divisors, whose sum is σ = 435019305909552. Its totient is φ = 33445260288000.

The previous prime is 132001120113259. The next prime is 132001120113407. The reversal of 132001120113300 is 3311021100231.

132001120113300 is a `hidden beast` number, since 1 + 3 + 200 + 1 + 120 + 11 + 330 + 0 = 666.

It can be written as a sum of positive squares in 24 ways, for example, as 43753621081104 + 88247499032196 = 6614652^2 + 9394014^2 .

It is a super-2 number, since 2×1320011201133002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 245252082 + ... + 245789718.

Almost surely, 2132001120113300 is an apocalyptic number.

132001120113300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132001120113300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (217509652954776).

132001120113300 is an abundant number, since it is smaller than the sum of its proper divisors (303018185796252).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132001120113300 is a wasteful number, since it uses less digits than its factorization.

132001120113300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 537868 (or 537858 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 132001120113300 its reverse (3311021100231), we get a palindrome (135312141213531).

The spelling of 132001120113300 in words is "one hundred thirty-two trillion, one billion, one hundred twenty million, one hundred thirteen thousand, three hundred".