1320011317 has 2 divisors, whose sum is σ = 1320011318. Its totient is φ = 1320011316.

The previous prime is 1320011311. The next prime is 1320011351. The reversal of 1320011317 is 7131100231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 885122001 + 434889316 = 29751^2 + 20854^2 .

It is an emirp because it is prime and its reverse (7131100231) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1320011317 is a prime.

It is a super-4 number, since 4×1320011317⁴ (a number of 38 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1320011294 and 1320011303.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1320011311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660005658 + 660005659.

It is an arithmetic number, because the mean of its divisors is an integer number (660005659).

Almost surely, 2^1320011317 is an apocalyptic number.

It is an amenable number.

1320011317 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320011317 is an equidigital number, since it uses as much as digits as its factorization.

1320011317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 126, while the sum is 19.

The square root of 1320011317 is about 36331.9599939227. The cubic root of 1320011317 is about 1096.9644454046.

Adding to 1320011317 its reverse (7131100231), we get a palindrome (8451111548).

The spelling of 1320011317 in words is "one billion, three hundred twenty million, eleven thousand, three hundred seventeen".