Base | Representation |
---|---|
bin | 1100000000010110010000… |
… | …0101101011101000000111 |
3 | 1201201220210121202100210111 |
4 | 3000011210011223220013 |
5 | 3212232313102232443 |
6 | 44024014251533451 |
7 | 2531451060156226 |
oct | 300054405535007 |
9 | 51656717670714 |
10 | 13200113711623 |
11 | 422a156078143 |
12 | 159232b45a287 |
13 | 7499c470c177 |
14 | 338c63266cbd |
15 | 17d572abd69d |
hex | c016416ba07 |
13200113711623 has 2 divisors, whose sum is σ = 13200113711624. Its totient is φ = 13200113711622.
The previous prime is 13200113711581. The next prime is 13200113711671. The reversal of 13200113711623 is 32611731100231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13200113711623 - 233 = 13191523777031 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13200113711923) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600056855811 + 6600056855812.
It is an arithmetic number, because the mean of its divisors is an integer number (6600056855812).
Almost surely, 213200113711623 is an apocalyptic number.
13200113711623 is a deficient number, since it is larger than the sum of its proper divisors (1).
13200113711623 is an equidigital number, since it uses as much as digits as its factorization.
13200113711623 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4536, while the sum is 31.
Adding to 13200113711623 its reverse (32611731100231), we get a palindrome (45811844811854).
The spelling of 13200113711623 in words is "thirteen trillion, two hundred billion, one hundred thirteen million, seven hundred eleven thousand, six hundred twenty-three".
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