Base | Representation |
---|---|
bin | 10011001101010110111… |
… | …010110111100001100111 |
3 | 11200012011222202222200112 |
4 | 103031112322313201213 |
5 | 133111341341412411 |
6 | 2450223344403235 |
7 | 164240105226251 |
oct | 23152672674147 |
9 | 4605158688615 |
10 | 1320013232231 |
11 | 4698a6069841 |
12 | 1939b191651b |
13 | 97627455ba5 |
14 | 47c63516cd1 |
15 | 2450ae06b8b |
hex | 13356eb7867 |
1320013232231 has 2 divisors, whose sum is σ = 1320013232232. Its totient is φ = 1320013232230.
The previous prime is 1320013232159. The next prime is 1320013232273. The reversal of 1320013232231 is 1322323100231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1320013232231 - 214 = 1320013215847 is a prime.
It is a super-2 number, since 2×13200132322312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1320013232197 and 1320013232206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1320013235231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660006616115 + 660006616116.
It is an arithmetic number, because the mean of its divisors is an integer number (660006616116).
Almost surely, 21320013232231 is an apocalyptic number.
1320013232231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320013232231 is an equidigital number, since it uses as much as digits as its factorization.
1320013232231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 1320013232231 its reverse (1322323100231), we get a palindrome (2642336332462).
The spelling of 1320013232231 in words is "one trillion, three hundred twenty billion, thirteen million, two hundred thirty-two thousand, two hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.064 sec. • engine limits •