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13200145111 = 56009235679
BaseRepresentation
bin11000100101100101…
…00011101011010111
31021001221101211221101
430102302203223113
5204013214120421
610021500530531
7645053245036
oct142262435327
937057354841
1013200145111
11566415743a
122684850a47
1313249aa06a
148d318871d
15523cd9191
hex312ca3ad7

13200145111 has 4 divisors (see below), whose sum is σ = 13200436800. Its totient is φ = 13199853424.

The previous prime is 13200145109. The next prime is 13200145129. The reversal of 13200145111 is 11154100231.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11154100231 = 17656123543.

It is a cyclic number.

It is not a de Polignac number, because 13200145111 - 21 = 13200145109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13200145171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61831 + ... + 173848.

It is an arithmetic number, because the mean of its divisors is an integer number (3300109200).

Almost surely, 213200145111 is an apocalyptic number.

13200145111 is a deficient number, since it is larger than the sum of its proper divisors (291689).

13200145111 is an equidigital number, since it uses as much as digits as its factorization.

13200145111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 291688.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 13200145111 its reverse (11154100231), we get a palindrome (24354245342).

The spelling of 13200145111 in words is "thirteen billion, two hundred million, one hundred forty-five thousand, one hundred eleven".

Divisors: 1 56009 235679 13200145111