13200222113 has 4 divisors (see below), whose sum is σ = 14215623828. Its totient is φ = 12184820400.

The previous prime is 13200222097. The next prime is 13200222151. The reversal of 13200222113 is 31122200231.

13200222113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3227603344 + 9972618769 = 56812^2 + 99863^2 .

It is a cyclic number.

It is not a de Polignac number, because 13200222113 - 2⁴ = 13200222097 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13200222091 and 13200222100.

It is not an unprimeable number, because it can be changed into a prime (13200222193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 507700838 + ... + 507700863.

It is an arithmetic number, because the mean of its divisors is an integer number (3553905957).

Almost surely, 2^13200222113 is an apocalyptic number.

13200222113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

13200222113 is a deficient number, since it is larger than the sum of its proper divisors (1015401715).

13200222113 is a wasteful number, since it uses less digits than its factorization.

13200222113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1015401714.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 13200222113 its reverse (31122200231), we get a palindrome (44322422344).

The spelling of 13200222113 in words is "thirteen billion, two hundred million, two hundred twenty-two thousand, one hundred thirteen".