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1320022300111 = 9011146490101
BaseRepresentation
bin10011001101010111011…
…101011101010111001111
311200012012121211200110221
4103031113131131113033
5133111401202100421
62450224311012211
7164240245264234
oct23152735352717
94605177750427
101320022300111
114699001a2659
121939b496a067
13976292ac3b8
1447c647d778b
152450bae8841
hex1335775d5cf

1320022300111 has 4 divisors (see below), whose sum is σ = 1320168799224. Its totient is φ = 1319875801000.

The previous prime is 1320022300073. The next prime is 1320022300117. The reversal of 1320022300111 is 1110032200231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1320022300111 - 213 = 1320022291919 is a prime.

It is a super-2 number, since 2×13200223001112 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1320022300117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 73236040 + ... + 73254061.

It is an arithmetic number, because the mean of its divisors is an integer number (330042199806).

Almost surely, 21320022300111 is an apocalyptic number.

1320022300111 is a deficient number, since it is larger than the sum of its proper divisors (146499113).

1320022300111 is an equidigital number, since it uses as much as digits as its factorization.

1320022300111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 146499112.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1320022300111 its reverse (1110032200231), we get a palindrome (2430054500342).

The spelling of 1320022300111 in words is "one trillion, three hundred twenty billion, twenty-two million, three hundred thousand, one hundred eleven".

Divisors: 1 9011 146490101 1320022300111