Base | Representation |
---|---|
bin | 11000100101100101… |
… | …11000011010010011 |
3 | 1021001221120011102201 |
4 | 30102302320122103 |
5 | 204013224330120 |
6 | 10021502424031 |
7 | 645054050446 |
oct | 142262703223 |
9 | 37057504381 |
10 | 13200230035 |
11 | 5664205223 |
12 | 2684892017 |
13 | 1324a09905 |
14 | 8d31ab65d |
15 | 523d0440a |
hex | 312cb8693 |
13200230035 has 32 divisors (see below), whose sum is σ = 16708664448. Its totient is φ = 9991618560.
The previous prime is 13200229997. The next prime is 13200230039. The reversal of 13200230035 is 53003200231.
It is not a de Polignac number, because 13200230035 - 219 = 13199705747 is a prime.
It is a super-2 number, since 2×132002300352 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13200229994 and 13200230021.
It is not an unprimeable number, because it can be changed into a prime (13200230039) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11448019 + ... + 11449171.
It is an arithmetic number, because the mean of its divisors is an integer number (522145764).
Almost surely, 213200230035 is an apocalyptic number.
13200230035 is a deficient number, since it is larger than the sum of its proper divisors (3508434413).
13200230035 is a wasteful number, since it uses less digits than its factorization.
13200230035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2175.
The product of its (nonzero) digits is 540, while the sum is 19.
Adding to 13200230035 its reverse (53003200231), we get a palindrome (66203430266).
The spelling of 13200230035 in words is "thirteen billion, two hundred million, two hundred thirty thousand, thirty-five".
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