Base | Representation |
---|---|
bin | 1100000000010110101101… |
… | …0110011101011101011011 |
3 | 1201201221010010000102101112 |
4 | 3000011223112131131123 |
5 | 3212233040300104210 |
6 | 44024034323210535 |
7 | 2531454066606614 |
oct | 300055326353533 |
9 | 51657103012345 |
10 | 13200235550555 |
11 | 422a208925579 |
12 | 1592364216a4b |
13 | 749a13a2b101 |
14 | 338c75500c0b |
15 | 17d57d638d05 |
hex | c016b59d75b |
13200235550555 has 8 divisors (see below), whose sum is σ = 15840343919472. Its totient is φ = 10560147601248.
The previous prime is 13200235550543. The next prime is 13200235550597. The reversal of 13200235550555 is 55505553200231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13200235550555 - 24 = 13200235550539 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3644744 + ... + 6299573.
It is an arithmetic number, because the mean of its divisors is an integer number (1980042989934).
Almost surely, 213200235550555 is an apocalyptic number.
13200235550555 is a deficient number, since it is larger than the sum of its proper divisors (2640108368917).
13200235550555 is an equidigital number, since it uses as much as digits as its factorization.
13200235550555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10209805.
The product of its (nonzero) digits is 562500, while the sum is 41.
Adding to 13200235550555 its reverse (55505553200231), we get a palindrome (68705788750786).
The spelling of 13200235550555 in words is "thirteen trillion, two hundred billion, two hundred thirty-five million, five hundred fifty thousand, five hundred fifty-five".
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