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13200235550555 = 52654839944317
BaseRepresentation
bin1100000000010110101101…
…0110011101011101011011
31201201221010010000102101112
43000011223112131131123
53212233040300104210
644024034323210535
72531454066606614
oct300055326353533
951657103012345
1013200235550555
11422a208925579
121592364216a4b
13749a13a2b101
14338c75500c0b
1517d57d638d05
hexc016b59d75b

13200235550555 has 8 divisors (see below), whose sum is σ = 15840343919472. Its totient is φ = 10560147601248.

The previous prime is 13200235550543. The next prime is 13200235550597. The reversal of 13200235550555 is 55505553200231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13200235550555 - 24 = 13200235550539 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3644744 + ... + 6299573.

It is an arithmetic number, because the mean of its divisors is an integer number (1980042989934).

Almost surely, 213200235550555 is an apocalyptic number.

13200235550555 is a deficient number, since it is larger than the sum of its proper divisors (2640108368917).

13200235550555 is an equidigital number, since it uses as much as digits as its factorization.

13200235550555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10209805.

The product of its (nonzero) digits is 562500, while the sum is 41.

Adding to 13200235550555 its reverse (55505553200231), we get a palindrome (68705788750786).

The spelling of 13200235550555 in words is "thirteen trillion, two hundred billion, two hundred thirty-five million, five hundred fifty thousand, five hundred fifty-five".

Divisors: 1 5 265483 1327415 9944317 49721585 2640047110111 13200235550555