Base | Representation |
---|---|
bin | 10011001101010111100… |
… | …100000010100000010101 |
3 | 11200012012202002022201202 |
4 | 103031113210002200111 |
5 | 133111402122300414 |
6 | 2450224412002245 |
7 | 164240266040336 |
oct | 23152744024025 |
9 | 4605182068652 |
10 | 1320024025109 |
11 | 469901170679 |
12 | 1939b5460385 |
13 | 976297645ca |
14 | 47c64b2628d |
15 | 2450bd399de |
hex | 13357902815 |
1320024025109 has 2 divisors, whose sum is σ = 1320024025110. Its totient is φ = 1320024025108.
The previous prime is 1320024025087. The next prime is 1320024025123. The reversal of 1320024025109 is 9015204200231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1307770642084 + 12253383025 = 1143578^2 + 110695^2 .
It is a cyclic number.
It is not a de Polignac number, because 1320024025109 - 28 = 1320024024853 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1320024025169) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660012012554 + 660012012555.
It is an arithmetic number, because the mean of its divisors is an integer number (660012012555).
Almost surely, 21320024025109 is an apocalyptic number.
It is an amenable number.
1320024025109 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320024025109 is an equidigital number, since it uses as much as digits as its factorization.
1320024025109 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 29.
The spelling of 1320024025109 in words is "one trillion, three hundred twenty billion, twenty-four million, twenty-five thousand, one hundred nine".
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