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132003141541 is a prime number
BaseRepresentation
bin111101011110000000…
…0000001011110100101
3110121201112012101020021
41322330000001132211
54130320301012131
6140350313235141
712352106122105
oct1727400013645
9417645171207
10132003141541
1150a89372007
12216bb702ab1
13c5a8baba9b
146563541205
153678b46e11
hex1ebc0017a5

132003141541 has 2 divisors, whose sum is σ = 132003141542. Its totient is φ = 132003141540.

The previous prime is 132003141533. The next prime is 132003141551. The reversal of 132003141541 is 145141300231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 70900245441 + 61102896100 = 266271^2 + 247190^2 .

It is a cyclic number.

It is not a de Polignac number, because 132003141541 - 23 = 132003141533 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132003141521) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66001570770 + 66001570771.

It is an arithmetic number, because the mean of its divisors is an integer number (66001570771).

Almost surely, 2132003141541 is an apocalyptic number.

It is an amenable number.

132003141541 is a deficient number, since it is larger than the sum of its proper divisors (1).

132003141541 is an equidigital number, since it uses as much as digits as its factorization.

132003141541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 132003141541 its reverse (145141300231), we get a palindrome (277144441772).

The spelling of 132003141541 in words is "one hundred thirty-two billion, three million, one hundred forty-one thousand, five hundred forty-one".