Base | Representation |
---|---|
bin | 1100000000010111011010… |
… | …0010110010110100000010 |
3 | 1201201221121012100202122102 |
4 | 3000011312202302310002 |
5 | 3212233431333124442 |
6 | 44024105112110402 |
7 | 2531461540000634 |
oct | 300056642626402 |
9 | 51657535322572 |
10 | 13200423333122 |
11 | 422a2a4923383 |
12 | 15923b7095402 |
13 | 749a438c845c |
14 | 338c92422a54 |
15 | 17d58ed7d232 |
hex | c01768b2d02 |
13200423333122 has 4 divisors (see below), whose sum is σ = 19800634999686. Its totient is φ = 6600211666560.
The previous prime is 13200423333107. The next prime is 13200423333127. The reversal of 13200423333122 is 22133332400231.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 13128947845321 + 71475487801 = 3623389^2 + 267349^2 .
It is not an unprimeable number, because it can be changed into a prime (13200423333127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3300105833279 + ... + 3300105833282.
Almost surely, 213200423333122 is an apocalyptic number.
13200423333122 is a deficient number, since it is larger than the sum of its proper divisors (6600211666564).
13200423333122 is an equidigital number, since it uses as much as digits as its factorization.
13200423333122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6600211666563.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 13200423333122 its reverse (22133332400231), we get a palindrome (35333755733353).
The spelling of 13200423333122 in words is "thirteen trillion, two hundred billion, four hundred twenty-three million, three hundred thirty-three thousand, one hundred twenty-two".
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