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13201004431 = 57143231017
BaseRepresentation
bin11000100101101011…
…10101011110001111
31021002000000111201001
430102311311132033
5204013424120211
610021531201131
7645063454246
oct142265653617
937060014631
1013201004431
11566469401a
122684ba61a7
131324c1b234
148d332d95d
15523e08ac1
hex312d7578f

13201004431 has 4 divisors (see below), whose sum is σ = 13201292592. Its totient is φ = 13200716272.

The previous prime is 13201004423. The next prime is 13201004473. The reversal of 13201004431 is 13440010231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13201004431 - 23 = 13201004423 is a prime.

It is a super-2 number, since 2×132010044312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13201004399 and 13201004408.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13201004231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58366 + ... + 172651.

It is an arithmetic number, because the mean of its divisors is an integer number (3300323148).

Almost surely, 213201004431 is an apocalyptic number.

13201004431 is a deficient number, since it is larger than the sum of its proper divisors (288161).

13201004431 is an equidigital number, since it uses as much as digits as its factorization.

13201004431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 288160.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 13201004431 its reverse (13440010231), we get a palindrome (26641014662).

The spelling of 13201004431 in words is "thirteen billion, two hundred one million, four thousand, four hundred thirty-one".

Divisors: 1 57143 231017 13201004431