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132010244231 is a prime number
BaseRepresentation
bin111101011110001101…
…1000111100010000111
3110121202000120020021212
41322330123013202013
54130324110303411
6140351125402035
712352223363465
oct1727433074207
9417660506255
10132010244231
1150a923833a8
1221701b6931b
13c5aa4c7968
14656446d835
15367959b68b
hex1ebc6c7887

132010244231 has 2 divisors, whose sum is σ = 132010244232. Its totient is φ = 132010244230.

The previous prime is 132010244227. The next prime is 132010244257. The reversal of 132010244231 is 132442010231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 132010244231 - 22 = 132010244227 is a prime.

It is a super-2 number, since 2×1320102442312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132010244197 and 132010244206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132010244131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66005122115 + 66005122116.

It is an arithmetic number, because the mean of its divisors is an integer number (66005122116).

Almost surely, 2132010244231 is an apocalyptic number.

132010244231 is a deficient number, since it is larger than the sum of its proper divisors (1).

132010244231 is an equidigital number, since it uses as much as digits as its factorization.

132010244231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 132010244231 its reverse (132442010231), we get a palindrome (264452254462).

The spelling of 132010244231 in words is "one hundred thirty-two billion, ten million, two hundred forty-four thousand, two hundred thirty-one".