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132010503 = 344003501
BaseRepresentation
bin1111101111001…
…01001000000111
3100012101211100220
413313211020013
5232243314003
621033235423
73162033162
oct767451007
9305354326
10132010503
1168575499
1238262b73
1321470931
1413764ad9
15b8c9353
hex7de5207

132010503 has 4 divisors (see below), whose sum is σ = 176014008. Its totient is φ = 88007000.

The previous prime is 132010477. The next prime is 132010507. The reversal of 132010503 is 305010231.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132010503 - 28 = 132010247 is a prime.

It is a super-3 number, since 3×1320105033 (a number of 25 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132010507) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22001748 + ... + 22001753.

It is an arithmetic number, because the mean of its divisors is an integer number (44003502).

Almost surely, 2132010503 is an apocalyptic number.

132010503 is a deficient number, since it is larger than the sum of its proper divisors (44003505).

132010503 is an equidigital number, since it uses as much as digits as its factorization.

132010503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44003504.

The product of its (nonzero) digits is 90, while the sum is 15.

The square root of 132010503 is about 11489.5823683892. The cubic root of 132010503 is about 509.1778410346.

Adding to 132010503 its reverse (305010231), we get a palindrome (437020734).

The spelling of 132010503 in words is "one hundred thirty-two million, ten thousand, five hundred three".

Divisors: 1 3 44003501 132010503