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132011000213143 = 251525940239893
BaseRepresentation
bin11110000001000000110100…
…110001100010111010010111
3122022102010110120200212100111
4132001000310301202322113
5114300332012023310033
61144433003303423451
736543323435401012
oct3601006461427227
9568363416625314
10132011000213143
1139076607111a57
1212980748a54b87
135887778ab9bcc
14248551b976379
15103dd981587cd
hex781034c62e97

132011000213143 has 4 divisors (see below), whose sum is σ = 132536940453288. Its totient is φ = 131485059973000.

The previous prime is 132011000213129. The next prime is 132011000213159. The reversal of 132011000213143 is 341312000110231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132011000213143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132011010213143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 262970119696 + ... + 262970120197.

It is an arithmetic number, because the mean of its divisors is an integer number (33134235113322).

Almost surely, 2132011000213143 is an apocalyptic number.

132011000213143 is a deficient number, since it is larger than the sum of its proper divisors (525940240145).

132011000213143 is an equidigital number, since it uses as much as digits as its factorization.

132011000213143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 525940240144.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 132011000213143 its reverse (341312000110231), we get a palindrome (473323000323374).

The spelling of 132011000213143 in words is "one hundred thirty-two trillion, eleven billion, two hundred thirteen thousand, one hundred forty-three".

Divisors: 1 251 525940239893 132011000213143