132011000223233 has 4 divisors (see below), whose sum is σ = 132156547082160. Its totient is φ = 131865453364308.

The previous prime is 132011000223203. The next prime is 132011000223251. The reversal of 132011000223233 is 332322000110231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 132011000223233 - 2²² = 132010996028929 is a prime.

It is a super-3 number, since 3×132011000223233³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132011000223199 and 132011000223208.

It is not an unprimeable number, because it can be changed into a prime (132011000223203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72773428103 + ... + 72773429916.

It is an arithmetic number, because the mean of its divisors is an integer number (33039136770540).

Almost surely, 2^{132011000223233} is an apocalyptic number.

It is an amenable number.

132011000223233 is a deficient number, since it is larger than the sum of its proper divisors (145546858927).

132011000223233 is an equidigital number, since it uses as much as digits as its factorization.

132011000223233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 145546858926.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 132011000223233 its reverse (332322000110231), we get a palindrome (464333000333464).

The spelling of 132011000223233 in words is "one hundred thirty-two trillion, eleven billion, two hundred twenty-three thousand, two hundred thirty-three".