13201100144431 has 2 divisors, whose sum is σ = 13201100144432. Its totient is φ = 13201100144430.

The previous prime is 13201100144429. The next prime is 13201100144497. The reversal of 13201100144431 is 13444100110231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13201100144431 - 2¹ = 13201100144429 is a prime.

It is a super-2 number, since 2×13201100144431² (a number of 27 digits) contains 22 as substring.

Together with 13201100144429, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 13201100144396 and 13201100144405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13201100141431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600550072215 + 6600550072216.

It is an arithmetic number, because the mean of its divisors is an integer number (6600550072216).

Almost surely, 2^{13201100144431} is an apocalyptic number.

13201100144431 is a deficient number, since it is larger than the sum of its proper divisors (1).

13201100144431 is an equidigital number, since it uses as much as digits as its factorization.

13201100144431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 13201100144431 its reverse (13444100110231), we get a palindrome (26645200254662).

The spelling of 13201100144431 in words is "thirteen trillion, two hundred one billion, one hundred million, one hundred forty-four thousand, four hundred thirty-one".