13201111403 has 4 divisors (see below), whose sum is σ = 13895906760. Its totient is φ = 12506316048.

The previous prime is 13201111397. The next prime is 13201111447. The reversal of 13201111403 is 30411110231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13201111403 is a prime.

It is a super-3 number, since 3×13201111403³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13201111003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 347397650 + ... + 347397687.

It is an arithmetic number, because the mean of its divisors is an integer number (3473976690).

Almost surely, 2^13201111403 is an apocalyptic number.

13201111403 is a deficient number, since it is larger than the sum of its proper divisors (694795357).

13201111403 is an equidigital number, since it uses as much as digits as its factorization.

13201111403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 694795356.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 13201111403 its reverse (30411110231), we get a palindrome (43612221634).

The spelling of 13201111403 in words is "thirteen billion, two hundred one million, one hundred eleven thousand, four hundred three".