1320114260159 has 2 divisors, whose sum is σ = 1320114260160. Its totient is φ = 1320114260158.

The previous prime is 1320114260041. The next prime is 1320114260161. The reversal of 1320114260159 is 9510624110231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1320114260159 - 2²⁴ = 1320097482943 is a prime.

Together with 1320114260161, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1320114230159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660057130079 + 660057130080.

It is an arithmetic number, because the mean of its divisors is an integer number (660057130080).

Almost surely, 2^{1320114260159} is an apocalyptic number.

1320114260159 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320114260159 is an equidigital number, since it uses as much as digits as its factorization.

1320114260159 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12960, while the sum is 35.

The spelling of 1320114260159 in words is "one trillion, three hundred twenty billion, one hundred fourteen million, two hundred sixty thousand, one hundred fifty-nine".