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132012401 = 643205307
BaseRepresentation
bin1111101111001…
…01100101110001
3100012101220222012
413313211211301
5232243344101
621033252305
73162041543
oct767454561
9305356865
10132012401
1168576964
1238264095
1321471761
1413765693
15b8c9bbb
hex7de5971

132012401 has 4 divisors (see below), whose sum is σ = 132218352. Its totient is φ = 131806452.

The previous prime is 132012389. The next prime is 132012403. The reversal of 132012401 is 104210231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 132012401 - 210 = 132011377 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132012403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102011 + ... + 103296.

It is an arithmetic number, because the mean of its divisors is an integer number (33054588).

Almost surely, 2132012401 is an apocalyptic number.

It is an amenable number.

132012401 is a deficient number, since it is larger than the sum of its proper divisors (205951).

132012401 is an equidigital number, since it uses as much as digits as its factorization.

132012401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 205950.

The product of its (nonzero) digits is 48, while the sum is 14.

The square root of 132012401 is about 11489.6649646541. The cubic root of 132012401 is about 509.1802812822.

Adding to 132012401 its reverse (104210231), we get a palindrome (236222632).

The spelling of 132012401 in words is "one hundred thirty-two million, twelve thousand, four hundred one".

Divisors: 1 643 205307 132012401