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1320124413017 is a prime number
BaseRepresentation
bin10011001101011101100…
…010111111010001011001
311200012110201222120001102
4103031131202333101121
5133112103322204032
62450242355401145
7164242625236424
oct23153542772131
94605421876042
101320124413017
114699528a7593
12193a22bb31b5
13976444b2837
1447c741b89bb
1524515a69362
hex1335d8bf459

1320124413017 has 2 divisors, whose sum is σ = 1320124413018. Its totient is φ = 1320124413016.

The previous prime is 1320124413001. The next prime is 1320124413019. The reversal of 1320124413017 is 7103144210231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1252259473936 + 67864939081 = 1119044^2 + 260509^2 .

It is a cyclic number.

It is not a de Polignac number, because 1320124413017 - 24 = 1320124413001 is a prime.

Together with 1320124413019, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1320124413019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660062206508 + 660062206509.

It is an arithmetic number, because the mean of its divisors is an integer number (660062206509).

Almost surely, 21320124413017 is an apocalyptic number.

It is an amenable number.

1320124413017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320124413017 is an equidigital number, since it uses as much as digits as its factorization.

1320124413017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 29.

Adding to 1320124413017 its reverse (7103144210231), we get a palindrome (8423268623248).

The spelling of 1320124413017 in words is "one trillion, three hundred twenty billion, one hundred twenty-four million, four hundred thirteen thousand, seventeen".