Base | Representation |
---|---|
bin | 111101011110010001… |
… | …1100000011011001101 |
3 | 110121202011200221220101 |
4 | 1322330203200123031 |
5 | 4130330141141331 |
6 | 140351244451101 |
7 | 12352251153052 |
oct | 1727443403315 |
9 | 417664627811 |
10 | 132012443341 |
11 | 50a93645649 |
12 | 21702849a91 |
13 | c5aaab78cc |
14 | 6564883029 |
15 | 3679883061 |
hex | 1ebc8e06cd |
132012443341 has 2 divisors, whose sum is σ = 132012443342. Its totient is φ = 132012443340.
The previous prime is 132012443323. The next prime is 132012443347. The reversal of 132012443341 is 143344210231.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 116492516100 + 15519927241 = 341310^2 + 124579^2 .
It is a cyclic number.
It is not a de Polignac number, because 132012443341 - 25 = 132012443309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132012443347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66006221670 + 66006221671.
It is an arithmetic number, because the mean of its divisors is an integer number (66006221671).
Almost surely, 2132012443341 is an apocalyptic number.
It is an amenable number.
132012443341 is a deficient number, since it is larger than the sum of its proper divisors (1).
132012443341 is an equidigital number, since it uses as much as digits as its factorization.
132012443341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 132012443341 its reverse (143344210231), we get a palindrome (275356653572).
It can be divided in two parts, 13201 and 2443341, that added together give a palindrome (2456542).
The spelling of 132012443341 in words is "one hundred thirty-two billion, twelve million, four hundred forty-three thousand, three hundred forty-one".
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