Base | Representation |
---|---|
bin | 1100000000011010011111… |
… | …1000011111001100110110 |
3 | 1201202000201212221212012010 |
4 | 3000012213320133030312 |
5 | 3212242130240303132 |
6 | 44024323202105050 |
7 | 2531521210635525 |
oct | 300064770371466 |
9 | 51660655855163 |
10 | 13201251103542 |
11 | 422a68a101567 |
12 | 15925a834b186 |
13 | 749b46252538 |
14 | 338d3033a4bc |
15 | 17d5dc88d6cc |
hex | c01a7e1f336 |
13201251103542 has 16 divisors (see below), whose sum is σ = 27116083348272. Its totient is φ = 4281486844320.
The previous prime is 13201251103517. The next prime is 13201251103567. The reversal of 13201251103542 is 24530115210231.
It is a happy number.
13201251103542 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (13201251103517) and next prime (13201251103567).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29732547309 + ... + 29732547752.
It is an arithmetic number, because the mean of its divisors is an integer number (1694755209267).
Almost surely, 213201251103542 is an apocalyptic number.
13201251103542 is an abundant number, since it is smaller than the sum of its proper divisors (13914832244730).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13201251103542 is a wasteful number, since it uses less digits than its factorization.
13201251103542 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59465095103.
The product of its (nonzero) digits is 7200, while the sum is 30.
Adding to 13201251103542 its reverse (24530115210231), we get a palindrome (37731366313773).
The spelling of 13201251103542 in words is "thirteen trillion, two hundred one billion, two hundred fifty-one million, one hundred three thousand, five hundred forty-two".
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