13201311211031 has 2 divisors, whose sum is σ = 13201311211032. Its totient is φ = 13201311211030.

The previous prime is 13201311211001. The next prime is 13201311211051. The reversal of 13201311211031 is 13011211310231.

13201311211031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an a-pointer prime, because the next prime (13201311211051) can be obtained adding 13201311211031 to its sum of digits (20).

It is a strong prime.

It is an emirp because it is prime and its reverse (13011211310231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13201311211031 - 2²² = 13201307016727 is a prime.

It is a super-2 number, since 2×13201311211031² (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 13201311210994 and 13201311211012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13201311211001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600655605515 + 6600655605516.

It is an arithmetic number, because the mean of its divisors is an integer number (6600655605516).

Almost surely, 2^{13201311211031} is an apocalyptic number.

13201311211031 is a deficient number, since it is larger than the sum of its proper divisors (1).

13201311211031 is an equidigital number, since it uses as much as digits as its factorization.

13201311211031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 13201311211031 its reverse (13011211310231), we get a palindrome (26212522521262).

The spelling of 13201311211031 in words is "thirteen trillion, two hundred one billion, three hundred eleven million, two hundred eleven thousand, thirty-one".