13201511143041 has 12 divisors (see below), whose sum is σ = 20535684000468. Its totient is φ = 8124006857184.

The previous prime is 13201511143001. The next prime is 13201511143091. The reversal of 13201511143041 is 14034111510231.

13201511143041 is a `hidden beast` number, since 1 + 3 + 2 + 0 + 1 + 511 + 143 + 0 + 4 + 1 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 1342131518016 + 11859379625025 = 1158504^2 + 3443745^2 .

It is not a de Polignac number, because 13201511143041 - 2⁶ = 13201511142977 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13201511142996 and 13201511143014.

It is not an unprimeable number, because it can be changed into a prime (13201511143001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 56416714170 + ... + 56416714403.

It is an arithmetic number, because the mean of its divisors is an integer number (1711307000039).

Almost surely, 2^{13201511143041} is an apocalyptic number.

It is an amenable number.

13201511143041 is a deficient number, since it is larger than the sum of its proper divisors (7334172857427).

13201511143041 is a wasteful number, since it uses less digits than its factorization.

13201511143041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 112833428592 (or 112833428589 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 27.

Adding to 13201511143041 its reverse (14034111510231), we get a palindrome (27235622653272).

The spelling of 13201511143041 in words is "thirteen trillion, two hundred one billion, five hundred eleven million, one hundred forty-three thousand, forty-one".