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13201541 is a prime number
BaseRepresentation
bin110010010111…
…000010000101
3220211201002222
4302113002011
511334422131
61150542125
7220132313
oct62270205
926751088
1013201541
1174a7571
124507945
132972b82
141a790b3
15125b87b
hexc97085

13201541 has 2 divisors, whose sum is σ = 13201542. Its totient is φ = 13201540.

The previous prime is 13201511. The next prime is 13201577. The reversal of 13201541 is 14510231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8579041 + 4622500 = 2929^2 + 2150^2 .

It is a cyclic number.

It is not a de Polignac number, because 13201541 - 214 = 13185157 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13201511) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600770 + 6600771.

It is an arithmetic number, because the mean of its divisors is an integer number (6600771).

Almost surely, 213201541 is an apocalyptic number.

It is an amenable number.

13201541 is a deficient number, since it is larger than the sum of its proper divisors (1).

13201541 is an equidigital number, since it uses as much as digits as its factorization.

13201541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 13201541 is about 3633.3924918731. The cubic root of 13201541 is about 236.3423464373.

Adding to 13201541 its reverse (14510231), we get a palindrome (27711772).

The spelling of 13201541 in words is "thirteen million, two hundred one thousand, five hundred forty-one".