Base | Representation |
---|---|
bin | 1100000000011101010010… |
… | …0101101000001011011111 |
3 | 1201202002200011021100222012 |
4 | 3000013110211220023133 |
5 | 3212300144242244203 |
6 | 44024525433541435 |
7 | 2531545616043242 |
oct | 300072445501337 |
9 | 51662604240865 |
10 | 13202001134303 |
11 | 422aa345127a3 |
12 | 159277757487b |
13 | 749c3575b017 |
14 | 338da1bb9259 |
15 | 17d633644bd8 |
hex | c01d49682df |
13202001134303 has 4 divisors (see below), whose sum is σ = 13302779769048. Its totient is φ = 13101222499560.
The previous prime is 13202001134293. The next prime is 13202001134339. The reversal of 13202001134303 is 30343110020231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13202001134303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13207001134303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50389317176 + ... + 50389317437.
It is an arithmetic number, because the mean of its divisors is an integer number (3325694942262).
Almost surely, 213202001134303 is an apocalyptic number.
13202001134303 is a deficient number, since it is larger than the sum of its proper divisors (100778634745).
13202001134303 is a wasteful number, since it uses less digits than its factorization.
13202001134303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 100778634744.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 13202001134303 its reverse (30343110020231), we get a palindrome (43545111154534).
The spelling of 13202001134303 in words is "thirteen trillion, two hundred two billion, one million, one hundred thirty-four thousand, three hundred three".
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