Base | Representation |
---|---|
bin | 11110000001001001001110… |
… | …000000010100100010111111 |
3 | 122022102222201201200210220200 |
4 | 132001021032000110202333 |
5 | 114301003441420421310 |
6 | 1144441053520414543 |
7 | 36544063001556513 |
oct | 3601111600244277 |
9 | 568388651623820 |
10 | 132020013451455 |
11 | 3907a411925338 |
12 | 12982443477453 |
13 | 5888584223a0c |
14 | 2485b34a36143 |
15 | 103e22459c9c0 |
hex | 78124e0148bf |
132020013451455 has 24 divisors (see below), whose sum is σ = 228849670207392. Its totient is φ = 70406064540864.
The previous prime is 132020013451397. The next prime is 132020013451471. The reversal of 132020013451455 is 554154310020231.
132020013451455 is a `hidden beast` number, since 1 + 3 + 2 + 0 + 2 + 0 + 0 + 134 + 514 + 5 + 5 = 666.
It is not a de Polignac number, because 132020013451455 - 211 = 132020013449407 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 95331979 + ... + 96706908.
It is an arithmetic number, because the mean of its divisors is an integer number (9535402925308).
Almost surely, 2132020013451455 is an apocalyptic number.
132020013451455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
132020013451455 is a deficient number, since it is larger than the sum of its proper divisors (96829656755937).
132020013451455 is a wasteful number, since it uses less digits than its factorization.
132020013451455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 192054175 (or 192054172 counting only the distinct ones).
The product of its (nonzero) digits is 72000, while the sum is 36.
Adding to 132020013451455 its reverse (554154310020231), we get a palindrome (686174323471686).
The spelling of 132020013451455 in words is "one hundred thirty-two trillion, twenty billion, thirteen million, four hundred fifty-one thousand, four hundred fifty-five".
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