Base | Representation |
---|---|
bin | 111101011110100000… |
… | …0011010010000010001 |
3 | 110121202200221220110022 |
4 | 1322331000122100101 |
5 | 4130334111121431 |
6 | 140352115113225 |
7 | 12352402441124 |
oct | 1727500322021 |
9 | 417680856408 |
10 | 132020020241 |
11 | 50a9795024a |
12 | 217052a2815 |
13 | c5ac53b595 |
14 | 65658963bb |
15 | 367a37d07b |
hex | 1ebd01a411 |
132020020241 has 2 divisors, whose sum is σ = 132020020242. Its totient is φ = 132020020240.
The previous prime is 132020020201. The next prime is 132020020243. The reversal of 132020020241 is 142020020231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 131766096016 + 253924225 = 362996^2 + 15935^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132020020241 is a prime.
Together with 132020020243, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (132020020243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66010010120 + 66010010121.
It is an arithmetic number, because the mean of its divisors is an integer number (66010010121).
Almost surely, 2132020020241 is an apocalyptic number.
It is an amenable number.
132020020241 is a deficient number, since it is larger than the sum of its proper divisors (1).
132020020241 is an equidigital number, since it uses as much as digits as its factorization.
132020020241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 17.
Adding to 132020020241 its reverse (142020020231), we get a palindrome (274040040472).
The spelling of 132020020241 in words is "one hundred thirty-two billion, twenty million, twenty thousand, two hundred forty-one".
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