Base | Representation |
---|---|
bin | 10011001101100010001… |
… | …011000000000110000101 |
3 | 11200012200010222221111021 |
4 | 103031202023000012011 |
5 | 133112233203323023 |
6 | 2450254210511141 |
7 | 164244556636564 |
oct | 23154213000605 |
9 | 4605603887437 |
10 | 1320202011013 |
11 | 469992688066 |
12 | 193a44b954b1 |
13 | 976575b1802 |
14 | 47c80617bdb |
15 | 2451c79635d |
hex | 133622c0185 |
1320202011013 has 2 divisors, whose sum is σ = 1320202011014. Its totient is φ = 1320202011012.
The previous prime is 1320202010977. The next prime is 1320202011017. The reversal of 1320202011013 is 3101102020231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1239964650369 + 80237360644 = 1113537^2 + 283262^2 .
It is an emirp because it is prime and its reverse (3101102020231) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1320202011013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1320202011017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660101005506 + 660101005507.
It is an arithmetic number, because the mean of its divisors is an integer number (660101005507).
Almost surely, 21320202011013 is an apocalyptic number.
It is an amenable number.
1320202011013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320202011013 is an equidigital number, since it uses as much as digits as its factorization.
1320202011013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 1320202011013 its reverse (3101102020231), we get a palindrome (4421304031244).
The spelling of 1320202011013 in words is "one trillion, three hundred twenty billion, two hundred two million, eleven thousand, thirteen".
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