Base | Representation |
---|---|
bin | 1100000000011101011001… |
… | …1100100110001000000111 |
3 | 1201202002202022221211010012 |
4 | 3000013112130212020013 |
5 | 3212300230233233111 |
6 | 44024532510220435 |
7 | 2531546445113531 |
oct | 300072634461007 |
9 | 51662668854105 |
10 | 13202032321031 |
11 | 422aa50083854 |
12 | 1592785ab471b |
13 | 749c3c05a1c8 |
14 | 338da5db6851 |
15 | 17d63625548b |
hex | c01d6726207 |
13202032321031 has 4 divisors (see below), whose sum is σ = 13202258476464. Its totient is φ = 13201806165600.
The previous prime is 13202032321019. The next prime is 13202032321043. The reversal of 13202032321031 is 13012323020231.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (13202032321019) and next prime (13202032321043).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13202032321031 is a prime.
It is a super-2 number, since 2×132020323210312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13202032320988 and 13202032321006.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13202002321031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 112990130 + ... + 113106911.
It is an arithmetic number, because the mean of its divisors is an integer number (3300564619116).
Almost surely, 213202032321031 is an apocalyptic number.
13202032321031 is a deficient number, since it is larger than the sum of its proper divisors (226155433).
13202032321031 is an equidigital number, since it uses as much as digits as its factorization.
13202032321031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 226155432.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 13202032321031 its reverse (13012323020231), we get a palindrome (26214355341262).
The spelling of 13202032321031 in words is "thirteen trillion, two hundred two billion, thirty-two million, three hundred twenty-one thousand, thirty-one".
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