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1320203264143 = 1996634187257
BaseRepresentation
bin10011001101100010001…
…111110010000010001111
311200012200020100121110111
4103031202033302002033
5133112234013423033
62450254253420451
7164244603406201
oct23154217620217
94605606317414
101320203264143
11469993363605
12193a4549a727
139765792ccca
1447c80862771
152451c9427cd
hex133623f208f

1320203264143 has 4 divisors (see below), whose sum is σ = 1326837451600. Its totient is φ = 1313569076688.

The previous prime is 1320203264101. The next prime is 1320203264161. The reversal of 1320203264143 is 3414623020231.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1320203264143 - 225 = 1320169709711 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1320203267143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3317093430 + ... + 3317093827.

It is an arithmetic number, because the mean of its divisors is an integer number (331709362900).

Almost surely, 21320203264143 is an apocalyptic number.

1320203264143 is a deficient number, since it is larger than the sum of its proper divisors (6634187457).

1320203264143 is an equidigital number, since it uses as much as digits as its factorization.

1320203264143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6634187456.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 1320203264143 its reverse (3414623020231), we get a palindrome (4734826284374).

The spelling of 1320203264143 in words is "one trillion, three hundred twenty billion, two hundred three million, two hundred sixty-four thousand, one hundred forty-three".

Divisors: 1 199 6634187257 1320203264143