Base | Representation |
---|---|
bin | 10011001101100010010… |
… | …011000001001000100101 |
3 | 11200012200021221201002012 |
4 | 103031202103001020211 |
5 | 133112234223044141 |
6 | 2450254323524005 |
7 | 164244613541255 |
oct | 23154223011045 |
9 | 4605607851065 |
10 | 1320204112421 |
11 | 469993892967 |
12 | 193a45829605 |
13 | 97657b6914c |
14 | 47c80a03965 |
15 | 2451ca5dceb |
hex | 133624c1225 |
1320204112421 has 4 divisors (see below), whose sum is σ = 1320308811744. Its totient is φ = 1320099413100.
The previous prime is 1320204112349. The next prime is 1320204112439. The reversal of 1320204112421 is 1242114020231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1320204112421 - 210 = 1320204111397 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1320204112441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52330745 + ... + 52355966.
It is an arithmetic number, because the mean of its divisors is an integer number (330077202936).
Almost surely, 21320204112421 is an apocalyptic number.
It is an amenable number.
1320204112421 is a deficient number, since it is larger than the sum of its proper divisors (104699323).
1320204112421 is a wasteful number, since it uses less digits than its factorization.
1320204112421 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 104699322.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 1320204112421 its reverse (1242114020231), we get a palindrome (2562318132652).
The spelling of 1320204112421 in words is "one trillion, three hundred twenty billion, two hundred four million, one hundred twelve thousand, four hundred twenty-one".
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