Base | Representation |
---|---|
bin | 1100000000011101110011… |
… | …1100011001101110011110 |
3 | 1201202010000221001122112101 |
4 | 3000013130330121232132 |
5 | 3212300441134302032 |
6 | 44024551402355314 |
7 | 2531552240445163 |
oct | 300073474315636 |
9 | 51663027048471 |
10 | 13202141322142 |
11 | 422aaa6662a13 |
12 | 15927b64bbb3a |
13 | 749c588029c6 |
14 | 338db666c06a |
15 | 17d640ad6de7 |
hex | c01dcf19b9e |
13202141322142 has 4 divisors (see below), whose sum is σ = 19803211983216. Its totient is φ = 6601070661070.
The previous prime is 13202141322077. The next prime is 13202141322169. The reversal of 13202141322142 is 24122314120231.
It is a semiprime because it is the product of two primes.
It is a self number, because there is not a number n which added to its sum of digits gives 13202141322142.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3300535330534 + ... + 3300535330537.
It is an arithmetic number, because the mean of its divisors is an integer number (4950802995804).
Almost surely, 213202141322142 is an apocalyptic number.
13202141322142 is a deficient number, since it is larger than the sum of its proper divisors (6601070661074).
13202141322142 is an equidigital number, since it uses as much as digits as its factorization.
13202141322142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6601070661073.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 13202141322142 its reverse (24122314120231), we get a palindrome (37324455442373).
The spelling of 13202141322142 in words is "thirteen trillion, two hundred two billion, one hundred forty-one million, three hundred twenty-two thousand, one hundred forty-two".
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