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132022011000000 = 26356112367991
BaseRepresentation
bin11110000001001011000101…
…000100010111010011000000
3122022110011212221102210101010
4132001023011010113103000
5114301022034304000000
61144442024035040520
736544163335501302
oct3601130504272300
9568404787383333
10132022011000000
1139080247448100
1212982900440140
1358888120202c4
142485c84053972
15103e2deb28d50
hex7812c51174c0

132022011000000 has 1176 divisors, whose sum is σ = 481725153839104. Its totient is φ = 31885920000000.

The previous prime is 132022010999993. The next prime is 132022011000001. The reversal of 132022011000000 is 110220231.

It is a super-2 number, since 2×1320220110000002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a self number, because there is not a number n which added to its sum of digits gives 132022011000000.

It is not an unprimeable number, because it can be changed into a prime (132022011000001) by changing a digit.

It is a polite number, since it can be written in 167 ways as a sum of consecutive naturals, for example, 133220999505 + ... + 133221000495.

Almost surely, 2132022011000000 is an apocalyptic number.

132022011000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132022011000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (240862576919552).

132022011000000 is an abundant number, since it is smaller than the sum of its proper divisors (349703142839104).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132022011000000 is an frugal number, since it uses more digits than its factorization.

132022011000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1425 (or 1379 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 12.

Adding to 132022011000000 its reverse (110220231), we get a palindrome (132022121220231).

The spelling of 132022011000000 in words is "one hundred thirty-two trillion, twenty-two billion, eleven million", and thus it is an aban number.