132022200302051 has 2 divisors, whose sum is σ = 132022200302052. Its totient is φ = 132022200302050.

The previous prime is 132022200302021. The next prime is 132022200302053. The reversal of 132022200302051 is 150203002220231.

It is a strong prime.

It is an emirp because it is prime and its reverse (150203002220231) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132022200302051 is a prime.

It is a super-2 number, since 2×132022200302051² (a number of 29 digits) contains 22 as substring.

Together with 132022200302053, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (132022200302053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66011100151025 + 66011100151026.

It is an arithmetic number, because the mean of its divisors is an integer number (66011100151026).

Almost surely, 2^{132022200302051} is an apocalyptic number.

132022200302051 is a deficient number, since it is larger than the sum of its proper divisors (1).

132022200302051 is an equidigital number, since it uses as much as digits as its factorization.

132022200302051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 132022200302051 its reverse (150203002220231), we get a palindrome (282225202522282).

The spelling of 132022200302051 in words is "one hundred thirty-two trillion, twenty-two billion, two hundred million, three hundred two thousand, fifty-one".