13202444041 has 4 divisors (see below), whose sum is σ = 13252643712. Its totient is φ = 13152244372.

The previous prime is 13202444033. The next prime is 13202444051. The reversal of 13202444041 is 14044420231.

13202444041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13202444041 - 2³ = 13202444033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13202443997 and 13202444015.

It is not an unprimeable number, because it can be changed into a prime (13202444011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25099441 + ... + 25099966.

It is an arithmetic number, because the mean of its divisors is an integer number (3313160928).

Almost surely, 2^13202444041 is an apocalyptic number.

It is an amenable number.

13202444041 is a deficient number, since it is larger than the sum of its proper divisors (50199671).

13202444041 is an equidigital number, since it uses as much as digits as its factorization.

13202444041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50199670.

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 13202444041 its reverse (14044420231), we get a palindrome (27246864272).

The spelling of 13202444041 in words is "thirteen billion, two hundred two million, four hundred forty-four thousand, forty-one".