Base | Representation |
---|---|
bin | 100111010110001… |
… | …1011000101101011 |
3 | 10102000022120101222 |
4 | 1032230123011223 |
5 | 10200442040024 |
6 | 335001532255 |
7 | 44501044151 |
oct | 11654330553 |
9 | 3360276358 |
10 | 1320268139 |
11 | 618290aa3 |
12 | 30a1a408b |
13 | 1806b3468 |
14 | c74b93d1 |
15 | 7ad9585e |
hex | 4eb1b16b |
1320268139 has 2 divisors, whose sum is σ = 1320268140. Its totient is φ = 1320268138.
The previous prime is 1320268121. The next prime is 1320268141. The reversal of 1320268139 is 9318620231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1320268139 is a prime.
Together with 1320268141, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 1320268099 and 1320268108.
It is not a weakly prime, because it can be changed into another prime (1320268639) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660134069 + 660134070.
It is an arithmetic number, because the mean of its divisors is an integer number (660134070).
Almost surely, 21320268139 is an apocalyptic number.
1320268139 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320268139 is an equidigital number, since it uses as much as digits as its factorization.
1320268139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 35.
The square root of 1320268139 is about 36335.4942033269. The cubic root of 1320268139 is about 1097.0355827578.
The spelling of 1320268139 in words is "one billion, three hundred twenty million, two hundred sixty-eight thousand, one hundred thirty-nine".
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