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13203013000003 is a prime number
BaseRepresentation
bin1100000000100001000011…
…1001100101101101000011
31201202012021200021110202121
43000020100321211231003
53212304232312000003
644025214101425111
72531612653544101
oct300102071455503
951665250243677
1013203013000003
114230403700442
1215929ba40b197
1374a067291018
1433905a334c71
1517d6923bbcbd
hexc0210e65b43

13203013000003 has 2 divisors, whose sum is σ = 13203013000004. Its totient is φ = 13203013000002.

The previous prime is 13203012999973. The next prime is 13203013000033. The reversal of 13203013000003 is 30000031030231.

It is a balanced prime because it is at equal distance from previous prime (13203012999973) and next prime (13203013000033).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13203013000003 is a prime.

It is not a weakly prime, because it can be changed into another prime (13203013000033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601506500001 + 6601506500002.

It is an arithmetic number, because the mean of its divisors is an integer number (6601506500002).

Almost surely, 213203013000003 is an apocalyptic number.

13203013000003 is a deficient number, since it is larger than the sum of its proper divisors (1).

13203013000003 is an equidigital number, since it uses as much as digits as its factorization.

13203013000003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 16.

Adding to 13203013000003 its reverse (30000031030231), we get a palindrome (43203044030234).

The spelling of 13203013000003 in words is "thirteen trillion, two hundred three billion, thirteen million, three", and thus it is an aban number.