Base | Representation |
---|---|
bin | 11110000001010011011100… |
… | …111010101001010010000000 |
3 | 122022111001002110210010211120 |
4 | 132001103130322221102000 |
5 | 114301143442231240000 |
6 | 1144450112102512240 |
7 | 36544632200540406 |
oct | 3601233472512200 |
9 | 568431073703746 |
10 | 132031001040000 |
11 | 39084040056227 |
12 | 129845ab135680 |
13 | 58896156c3cba |
14 | 2486497dd5476 |
15 | 103e668ed96a0 |
hex | 7814dcea9480 |
132031001040000 has 320 divisors, whose sum is σ = 445428275825280. Its totient is φ = 34631078400000.
The previous prime is 132031001039969. The next prime is 132031001040017. The reversal of 132031001040000 is 40100130231.
It is a tau number, because it is divible by the number of its divisors (320).
It is a Harshad number since it is a multiple of its sum of digits (15).
It is an unprimeable number.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 10130745 + ... + 19149255.
It is an arithmetic number, because the mean of its divisors is an integer number (1391963361954).
Almost surely, 2132031001040000 is an apocalyptic number.
132031001040000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 132031001040000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (222714137912640).
132031001040000 is an abundant number, since it is smaller than the sum of its proper divisors (313397274785280).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132031001040000 is an frugal number, since it uses more digits than its factorization.
132031001040000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9018609 (or 9018582 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 132031001040000 its reverse (40100130231), we get a palindrome (132071101170231).
The spelling of 132031001040000 in words is "one hundred thirty-two trillion, thirty-one billion, one million, forty thousand".
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