Base | Representation |
---|---|
bin | 10011001101101000100… |
… | …111000010001111011010 |
3 | 11200012221200020112021001 |
4 | 103031220213002033122 |
5 | 133112443331220010 |
6 | 2450313025535214 |
7 | 164250341011660 |
oct | 23155047021732 |
9 | 4605850215231 |
10 | 1320310023130 |
11 | 469a3865117a |
12 | 193a751a450a |
13 | 97673a9c0c7 |
14 | 47c90ad2c30 |
15 | 24526ecec3a |
hex | 133689c23da |
1320310023130 has 64 divisors (see below), whose sum is σ = 2728533600000. Its totient is φ = 450604551168.
The previous prime is 1320310023127. The next prime is 1320310023139. The reversal of 1320310023130 is 313200130231.
It is a super-2 number, since 2×13203100231302 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1320310023098 and 1320310023107.
It is not an unprimeable number, because it can be changed into a prime (1320310023139) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13539186 + ... + 13636354.
It is an arithmetic number, because the mean of its divisors is an integer number (42633337500).
Almost surely, 21320310023130 is an apocalyptic number.
1320310023130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1320310023130 is an abundant number, since it is smaller than the sum of its proper divisors (1408223576870).
1320310023130 is a wasteful number, since it uses less digits than its factorization.
1320310023130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 98071.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 1320310023130 its reverse (313200130231), we get a palindrome (1633510153361).
The spelling of 1320310023130 in words is "one trillion, three hundred twenty billion, three hundred ten million, twenty-three thousand, one hundred thirty".
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