Search a number
-
+
132031140000 = 2535421110429
BaseRepresentation
bin111101011110110101…
…0110101000010100000
3110121210110212211220020
41322331222311002200
54130344432440000
6140353153313440
712352566113214
oct1727552650240
9417713784806
10132031140000
1150aa3155731
1221708b65880
13c5b1932a16
14656714c944
15367b327ba0
hex1ebdab50a0

132031140000 has 240 divisors, whose sum is σ = 435182821920. Its totient is φ = 35038080000.

The previous prime is 132031139963. The next prime is 132031140079. The reversal of 132031140000 is 41130231.

It is a tau number, because it is divible by the number of its divisors (240).

It is a super-3 number, since 3×1320311400003 (a number of 34 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 12654786 + ... + 12665214.

It is an arithmetic number, because the mean of its divisors is an integer number (1813261758).

Almost surely, 2132031140000 is an apocalyptic number.

132031140000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132031140000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (217591410960).

132031140000 is an abundant number, since it is smaller than the sum of its proper divisors (303151681920).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132031140000 is a wasteful number, since it uses less digits than its factorization.

132031140000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10673 (or 10650 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 132031140000 its reverse (41130231), we get a palindrome (132072270231).

The spelling of 132031140000 in words is "one hundred thirty-two billion, thirty-one million, one hundred forty thousand".